Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
357 views
in Technique[技术] by (71.8m points)

java - Recursive use of Stream.flatMap()

Consider the following class:

public class Order {

    private String id;

    private List<Order> orders = new ArrayList<>();

    @Override
    public String toString() {
        return this.id;
    }

    // getters & setters
}

NOTE: It is important to note that I cannot modify this class, because I'm consuming it from an external API.

Also consider the following hierarchy of orders:

Order o1 = new Order();
o1.setId("1");
Order o11 = new Order();
o11.setId("1.1");
Order o111 = new Order();
o111.setId("1.1.1");
List<Order> o11Children = new ArrayList<>(Arrays.asList(o111));
o11.setOrders(o11Children);

Order o12 = new Order();
o12.setId("1.2");
List<Order> o1Children = new ArrayList<>(Arrays.asList(o11, o12));
o1.setOrders(o1Children);

Order o2 = new Order();
o2.setId("2");
Order o21 = new Order();
o21.setId("2.1");
Order o22 = new Order();
o22.setId("2.2");
Order o23 = new Order();
o23.setId("2.3");
List<Order> o2Children = new ArrayList<>(Arrays.asList(o21, o22, o23));
o2.setOrders(o2Children);

List<Order> orders = new ArrayList<>(Arrays.asList(o1, o2));

Which could be visually represented this way:

1
1.1
1.1.1
1.2
2
2.1
2.2
2.3

Now, I want to flatten this hierarchy of orders into a List, so that I get the following:

[1, 1.1, 1.1.1, 1.2, 2, 2.1, 2.2, 2.3]

I've managed to do it by recursively using flatMap() (along with a helper class), as follows:

List<Order> flattened = orders.stream()
    .flatMap(Helper::flatten)
    .collect(Collectors.toList());

This is the helper class:

public final class Helper {

    private Helper() {
    }

    public static Stream<Order> flatten(Order order) {
        return Stream.concat(
            Stream.of(order), 
            order.getOrders().stream().flatMap(Helper::flatten)); // recursion here
    }
}

The following line:

System.out.println(flattened);

Produces the following output:

[1, 1.1, 1.1.1, 1.2, 2, 2.1, 2.2, 2.3]

So far so good. The result is absolutely correct.

However, after reading this question, I had some concerns regarding the usage of flatMap() within a recursive method. Particularly, I wanted to know how the stream was being expanded (if that's the term). So I modified the Helper class and used peek(System.out::println) to check this:

public static final class Helper {

    private Helper() {
    }

    public static Stream<Order> flatten(Order order) {
        return Stream.concat(
            Stream.of(order), 
            order.getOrders().stream().flatMap(Helper::flatten))
        .peek(System.out::println);
    }
}

And the output was:

1
1.1
1.1
1.1.1
1.1.1
1.1.1
1.2
1.2
2
2.1
2.1
2.2
2.2
2.3
2.3

I'm not sure if this is the output that should be printed.

So, I wonder if it's OK to let intermediate streams contain repeated elements. Furthermore, what are the pros and cons of this approach? Is it correct, after all, to use flatMap() this way? Is there a better way to achieve the same?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Well, I used the same pattern with a generic Tree class and didn’t have a wrong feeling with it. The only difference is, that the Tree class itself offered a children() and allDescendants() methods, both returning a Stream and the latter building on the former. This is related to “Should I return a Collection or a Stream?” and “Naming java methods that return streams”.

From a Streams perspective, there is no difference between a flatMap to children of a different type (i.e. when traversing a property) and a flatMap to children of the same type. There is also no problem if the returned stream contains the same element again, as there is no relationship between the elements of the streams. In principle, you can use flatMap as a filter operation, using the pattern flatMap(x -> condition? Stream.of(x): Stream.empty()). It’s also possible to use it to duplicate elements like in this answer.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...